Recent content by fedderenator

He's talking about cross-sections I'm pretty sure...first what you want to do it find the height of your chunk, and then, using the standard formula for the geometric shape, set up the definite integral and evaluate it if necessary...

The main point is that there are actually multiple ways to write the domain, as long as they are consistent with the fact that everything under the root must be nonnegative and the denominator of the fraction cannot ever be zero...in order to ensure that, your professor has given you an accurate...

B(x) cannot equal zero, it is in the denominator, so that is definitely not right...and I already told you that A(x)/B(x) ≥ 0...it can equal zero as well...but if you multiply both sides of the inequality by B(x) (which you can do), you find that A(x) ≥ 0 which is the correct domain because A(x)...

Ok, I figured the answer out (its not 1.80 microT or 3.60 microT because I had tried both of those before)...it is completely off base from what we were attempting to do...first of all you were on the right track with half of my answer, 1.80 microT because you didn't include the mu_0*I term from...

I submitted that and I got it wrong...when I calculated, I got 3.60 microT

Is it... \sqrt{\frac{A(x)}{B(x)}} ?

Well, essentially what he wants you to say, is that the ratio of A(x) to B(x) must be greater than zero, rather than each individual subfunction...so basically, you could rewrite the domain as {x∈ R : A(x)/B(x) ≥ 0 and B(x) > 0 }, but technically, the other domain that we already wrote is...

number four is incorrect because A(x) can equal zero...I don't know if I mentioned that, but there are never problem spots in the numerator unless there is a radical in the numerator...in this case, f(x) = A(x)/sqrt(B(x)) so there is no problems in the numerator...the only problem is in the...

Try synthetic division...

The one point about this problem is to realize that in order for x to be an element of the real numbers, the radicand (or the stuff under the square root) cannot be negative, so your objective is to find a domain where there are no imaginary numbers and one would not have to divide by zero...

LMAO divide both sides by a factorial...wow...

I understand it would be 2pir for a circle, but that makes absolutely no sense with the value that they gave us because they are asking the magnetic field 5 cm from the center of the plate separation, not from the center of the actual plates themselves...and by the way, is everything else right...

so would it be dE/dt*A where A is the circular area of the plates...and then int(ds) would be the radius away from the center given... B = (mu_0*I + epsilon_0*mu_0*dE/dt*A)/r ? where r is the "radius" away from the center of the parallel plate configuration (5.00 cm)

Well, none of them really give B in terms of dE/dt, but the equation \oint(Bds) = \mu_{0}I + \epsilon_{0}\mu_{0}\frac{d\Phi_{E}}{dt}... gives B in terms of electric flux... and then also, the Lorentz force law also describes a relationship between B and E fields... F = q(E + vB)...

Homework Statement A 0.450 A current is charging a capacitor that has circular plates 14.0 cm in radius. (a) If the plate separation is 4.00 mm, what is the time rate of increase of electric field between the plates? Answer: 8.26e5 MV/m/s (b) What is the magnitude of the magnetic field...