(n+1) <100000 how do i find n?

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Homework Help Overview

The problem involves finding the integer value of n such that (n+1)! is less than 100,000. Participants are exploring methods to approach this factorial inequality analytically rather than relying solely on calculators.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest using Stirling's approximation for a quick estimate, while others express a desire to find a more analytical solution. There are discussions about trial and error methods, with some participants questioning the rationale behind certain approaches and calculations.

Discussion Status

The discussion is ongoing, with various methods being proposed and explored. Some participants have provided numerical examples of factorials to illustrate their reasoning, while others have raised questions about the validity of certain operations mentioned in the thread.

Contextual Notes

Participants are navigating the constraints of the problem, including the need for an analytical approach and the limitations of using calculators. There is also a sense of uncertainty regarding the operations suggested by some participants.

hangainlover
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Homework Statement


(n+1)! <100000 how do i find n?


Homework Equations





The Attempt at a Solution


I can find it by plugging it into the calculator
but i want to do it analytically.
Thanks
 
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hangainlover said:
I can find it by plugging it into the calculator
but i want to do it analytically.
Why? :confused:
 
I agree with Hurkyl. Just do it by trial and error using a calculator.
 
You should be expecting something really small for n.
Sometimes you have to take a little time to meditate on the question before you start(considering what approach you want to take and by your intuition will it lead you to anywhere).

Thus, if you work it out ,

0! = 1 By def^{n}
1! = 1
2! = 2
3! = 3x2 = 6
4! = 4x3x2 = 24 (realizing that its slightly smaller than the factor 25 of 10,000)
5! = 5x4x3x2 = 5x24 < 400x25 = 10,000
6! = 6x5x4x3x2 = 30x24 < 400x25 = 10,000
7! = 210x24 < 400x25 = 10,000
8! = 1680 x 24 ( you realize that one of the factor is way larger than 400 and another is smaller than 24 , inconclusive)

Consider using a factor larger than 25 ... how about 26? 2x13 .. we have yet to reach 13! , analogously you will choose 28 as your choice.

8! = 4x360x28 > 2x200x25 = 10,000 Now you may draw a conclusion.
 
Last edited:
divide both sides by a factorial. 100000/ ! = n +1. n = 100000/! - 1.
 
dacruick said:
divide both sides by a factorial. 100000/ ! = n +1. n = 100000/! - 1.

What operation is that?
 
dacruick said:
divide both sides by a factorial. 100000/ ! = n +1. n = 100000/! - 1.
This makes no sense at all.
 
LMAO divide both sides by a factorial...wow...
 

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