How can I factor a cubic equation by hand to find the x-intercepts?

  • Thread starter Thread starter DecayProduct
  • Start date Start date
  • Tags Tags
    Cubic Factoring
Click For Summary

Homework Help Overview

The discussion revolves around the problem of factoring a cubic equation, specifically f(x)=x^{3}+3x^{2}-9x+3, to find its x-intercepts. The original poster is exploring methods to achieve this by hand, referencing a graph for context.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to factor the cubic equation but struggles with the quadratic component and questions the validity of their assumptions about factoring. Some participants suggest using the rational roots test and synthetic division as potential methods for finding roots.

Discussion Status

Participants are exploring various methods for factoring the cubic equation, with some offering guidance on techniques like synthetic division and the rational roots test. There is an acknowledgment of the challenges faced in deriving the roots without numerical approximations.

Contextual Notes

The original poster is not a student and is working from a problem found in a book, which may influence the nature of the discussion. Additionally, there are reminders about posting guidelines for textbook-style exercises within the appropriate forum.

DecayProduct
Messages
67
Reaction score
0
This is not a homework question, per se, because I'm not a student. But it is a problem I found in a book. Actually, the problem doesn't involve what I'm going to ask, but it did present an opportunity for me to explore the subject.

I have the graph of f(x)=x^{3}+3x^{2}-9x+3. I know the x intercepts of the function from looking at the graph, what I want to know is how to factor the equation by hand to derive those intercepts.

x(x^{2}+3x^{2}-9)=-3 doesn't help because factoring the quadratic in the middle gives me the zeros of that particular piece, which are meaningless, because I'm not looking for those zeros. I've tried factoring by pieces, but I can't get the right products to pop out.

Surely, because the graph exists at all, and because the function is continuous across the x-axis, then there must be a way to factor the zeros out of f(x)? Or am I totally off base with that assumption?
 
Physics news on Phys.org
If you know that the number a is a root of the equation, then it is trivial to factor out the binomial x - a from the cubic polynomial. Otherwise, you can only really get as far as the rational roots test before having to resort to iteration algorithms to converge to irrational roots (ie., the Newton-Raphson method).
 
If the http://en.wikipedia.org/wiki/Rational_root_theorem" without resorting to numerical approximations. (See the two clickable links in that previous sentence for more details.)

p.s...

Moderator's note:

Any textbook-style exercises are to be posted in the appropriate forum in our https://www.physicsforums.com/forumdisplay.php?f=152" area. This should be done even if the problem is part of one's independent study. Basically, it's prohibitively difficult to moderate a lot of questions based on whether it's for an actual course assignment.

I have gone ahead and moved this thread to our "Homework" forums.
 
Last edited by a moderator:
Try synthetic division...
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
6
Views
56K
  • · Replies 9 ·
Replies
9
Views
35K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
4
Views
3K