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Ramp, block, and elastic potential energy
I found the gravitational energy by multiplying the amount of gravitational force acting parallel to the ramp (6.81 N) by the distance it acts for: ≈(6.81)(0.9) ≈6.129 J Using the gravitational potential energy equation, I get the same answer: =mgh =(4)(9.81)(sin(10)*0.9) ≈6.13 J- fereas
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- Forum: Introductory Physics Homework Help
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Ramp, block, and elastic potential energy
Homework Statement The spring in the figure below is initially compressed by 0.4 m in the position shown. If released from this position, block A travels 0.9 m before coming to a stop. The kinetic coefficient of friction is 0.8. What is the spring constant? (The spring is not fastened to...- fereas
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- Block Elastic Elastic potential energy Energy Potential Potential energy Ramp
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- Forum: Introductory Physics Homework Help