Recent content by foxtrot1985

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    Integrating $\int {\frac{sin^{2}x}{1+sin^{2}x}dx}$ Solution

    If you mean 2tan^-1 t, I can get this part. But what about the 2nd function?
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    Integrating $\int {\frac{sin^{2}x}{1+sin^{2}x}dx}$ Solution

    Hmm after I do partial fractions, I get \int {\frac{2}{1+t^{2}} + {\frac{-2t^{2}-2}{(1+6t^{2}+t^{4})} dt} After this, I do not know what's the next step. Kindly advise. Thanks.
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    Integrating $\int {\frac{sin^{2}x}{1+sin^{2}x}dx}$ Solution

    Homework Statement \int {\frac{sin^{2}x}{1+sin^{2}x}dx} Homework Equations Let t = tan x/2, then dx = 2/(1+t^2) and sin x = 2t / (1+t^2) The Attempt at a Solution I got up to the point where \int {\frac{8t^{2}}{(1+6t^{2}+t^{4})(1+t^{2})} dt}. Not sure if I'm on the right track...