Integrating $\int {\frac{sin^{2}x}{1+sin^{2}x}dx}$ Solution

[foxtrot1985]

Homework Statement

\int {\frac{sin^{2}x}{1+sin^{2}x}dx}

Homework Equations

Let t = tan x/2, then dx = 2/(1+t^2) and sin x = 2t / (1+t^2)

The Attempt at a Solution

I got up to the point where \int {\frac{8t^{2}}{(1+6t^{2}+t^{4})(1+t^{2})} dt}. Not sure if I'm on the right track and if I am, do I use partial fractions after this?

The final answer is attached. Can't really make out the handwriting :/

 

[Mindscrape]

Yes, it looks like partial fractions is the way to go after your substitution.

 

[foxtrot1985]

Hmm after I do partial fractions, I get
\int {\frac{2}{1+t^{2}} + {\frac{-2t^{2}-2}{(1+6t^{2}+t^{4})} dt}

After this, I do not know what's the next step. Kindly advise. Thanks.

 

[ziad1985]

you are summing 2 functions of t , one of these two look very much like a derivative of a certain function..

 

[foxtrot1985]

If you mean 2tan^-1 t, I can get this part. But what about the 2nd function?