Recent content by fran1942

Hello, I am having some trouble with the following set of questions. I include them along with my answers. Would anyone be able to confirm if I am correct here ? Thanks kindly for any help. Suppose a RISC machine uses overlapping register windows for passing parameters between procedures. The...

Hello, I need to design a circuit (3-bit priority encoder) whereby: - if input X =1, then outputs B1=1, B0=1 - if inputs X=0, Y=1, then outputs B1=1, B0=0 - if inputs X=0, Y=0, Z=1 then outputs B1=0, B2=1 - if all 3 inputs = 0, then outputs B1=0, B0=0 Would this be the correct way to...

Hello, I am trying to prove that the following two expressions are the inverse of each other by using deMorgan's theorem. i) X = A(B+C) ii) X = A' + B'C' I am having trouble doing this. Can this actually be achieved with these two expressions ? Thank you for any help.

Hello, I can understand most boolean simplifications however I cannot grasp this one: (A+C+D)(A+C+'D)((A+'C+D)(A+'B) where the ' symbol represents a NOT. Without using Karnaugh maps can someone please tell me how to go about simplifying this expression ? Thank you kindly for any help.

Hello, I am trying to represent a binary word as different types of encoding. I am OK with all the different forms apart from the last one. That last step is to represent it as RLL(2,7). However I do not know how to do it. After researching on the internet, it seems very complicated to do this...

hello, thanks kindly for your help. However, I just can't see what I have done wrong with that final operation on the first question. I ended up with remainder 11 after I performed the XOR operation on 1000 and 1011. How could I get another result. I thought the rule with modulo 2 division...

Hello, could someone please confirm if have done the modulo 2 division in order to find the CRC code word for these two correctly. 1) using the CRC polynominal 1011, for the information word 0101 1001 (attached image 1 is my attempt) 2) using the CRC polynominal 1101, for the information word...

Hello, I am trying to understand the following modulo 2 long division. I understand that 1101 goes into 1111, so you write a 1 on the top. The next stage after 'XOR'ing is to bring down the 1. Now, 1101 does not go into 101, so you write a 0 at the top. So far so so good. Now you bring down...

Homework Statement If a transmission line operating at 250 MHz has a characteristic impedance Z0 of 50 Ohm and propagation coefficient γ = 0.4 + j7.5 per meter, calculate its primary coefficients R, L, C and G. Hello, I do not know what formula I can use to solve this problem. If anyone...

Hello, I have taken the attached filter response graph of filter gain to frequency created in micro-Cap. My cutoff frequency is 1kHz. How can I measure the roll off rate in db/Dec based on this graph ? Perhaps there is a formula ? Any help would be appreciated.

Hello, I am wondering what sort of visual differences you would see between an AM modulated waveform with carrier and a DSBSC waveform (suppressed carrier) in the time domain on an oscilloscope. Any help would be appreciated.

Hello, looking at the attached graph of noise voltage to frequency, I am trying to understand (from a noise point of view) why AM and FM broadcasts at the frequencies they do ? Can anyone offer any suggestions please ? Thank you.

Hello, I am trying to integrate 1/(x^2-1). Apparently this can be solved by using trig substitution involving tan ? Can someone please help me to understand how to go about it. Thanks kindly for any help.

sorry, I attached the wrong image. This is the O-pad attachment. What does it mean when I get a negative value from one of the resistor formula calculations (as I am in this case). Obviously I can't have negative Ohm resistors ?

Hello, I am trying to work out the resistor values for an 'O' attenuator. I am using the attached formula to work out resistor 3's value. My values to insert into this formula are: Input impedance (Z1) = 50 Ohm Load impedance (Z2) = 600 Ohm a =1.995 However when I substitute these figures I am...