Recent content by Fre4k

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    Special Relativity: Force applied to a bar

    Actually, I was able to do it for the rigid bar, it's the deformed one that I'm having difficulty with. I found that the bar gained ΔE = Fdl/2, but I can't see how this energy transforms.
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    Special Relativity: Force applied to a bar

    Up. The thing is, I can't see how the deformation would affect the bar in the moving reference frame.
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    Special Relativity: Force applied to a bar

    Homework Statement Two forces of equal magnitude are applied simultaneously on the ends of a bar of length L. In another reference frame, moving with velocity v relative to the bar (with v being parallel to the length L), the forces are not applied at the same time, generating momentum. I...
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    Mathematica: position vs time in a spring

    Thanks guys, I'll just use the other equation.
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    Mathematica: position vs time in a spring

    This is what I'm doing: m := 0.5(* kg *) k := 60(* N/m *) μ := 0.4 g := 10(* m/s² *) DSolve[{x''[t] + (k/m)*x[t] + μ*g*Sign[x'[t]] == 0, x[0] == 3, x'[0] == 4}, x[t], t]
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    Mathematica: position vs time in a spring

    Thanks, I understand it now, but when I try to solve this equation using Mathematica nothing happens. The program sends back to me the same thing I typed and no error messages.
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    Mathematica: position vs time in a spring

    It worked, but I still don't get it. I thought friction was independent of velocity, so what is this "friction"?
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    Mathematica: position vs time in a spring

    Homework Statement Plot the position vs time graph of an object attached to a spring. m = 0.5 kg k = 60 N/m x[0] = 3 m v[0] = 4 m/s Homework Equations d²x/dt² + (k/m)*x = 0 The Attempt at a Solution I solved the differential equation using DSolve and plotted the resulting...
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    Limit of (1+ln x)/x as x -> 0?

    Ok, I got it. It's quite simple actually, duh.
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    Limit of (1+ln x)/x as x -> 0?

    Homework Statement lim (1+ln x)/x = ? x->0 Homework Equations The Attempt at a Solution lim 1/x + (ln x)/x x->0 I know that (ln x)/x approaches -infinity faster than 1/x approaches infinity so the limit = -infinity, but how do I express this analytically?