- #1
Fre4k
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Homework Statement
Two forces of equal magnitude are applied simultaneously on the ends of a bar of length L. In another reference frame, moving with velocity v relative to the bar (with v being parallel to the length L), the forces are not applied at the same time, generating momentum. I have to analyze what happens to the energy and momentum of the bar on both reference frames in two cases:
1. Considering the bar is rigid.
2. The bar is not rigid.
Homework Equations
Special Relativity formulas
F=kx
The Attempt at a Solution
I was able to do it for the rigid bar, but not the other case. This is what I did:
I considered F = k . dl (dl being the deformation of the bar). The bar gained an energy equal to kdl²/2, or ΔE = Fdl/2. I don't know what to do now.
Also, I'm sorry for my crappy english. I tried to explain it the best I could.