Recent content by gcharles_42

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    Solving Sliding Friction Homework: F=ma & Nuk

    Homework Statement So say there was some object on a Horizontal surface. id there was some force on (not constant, but a hit or something) this object and there was a sliding friction between the surface and the object. How would that factor into the F=ma formula? and what if you are given a...
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    How Do You Calculate Speed and Normal Forces in a Loop-the-Loop Problem?

    So for a) v = 3(.98) 1.9(.8) = 1/2(3)v^2
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    How Do You Calculate Speed and Normal Forces in a Loop-the-Loop Problem?

    Homework Statement In Fig. 8-28, a small block of mass m = 3.0 kg can slide along the frictionless loop-the-loop. The loop has radius R = 0.80 m. The block is released from rest at point P, at height h = 2.9R above the bottom of the loop. I attatched a picture (a) Find the speed of the...
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    Calculating Force Components for Conservative Potential Energy Function

    Homework Statement A particle of mass m = 10 kg moves in space under the action of a conservative force. Its potential energy is given by PE = 2xyz + 3z2 + 4yx + 16 where PE is in Joules and x, y, and z are in meters. Calculate the x-, y-, and z-components of the force on the particle...
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    How Do Friction and Human Force Affect Work Done on a Box?

    Homework Statement A box of mass 45 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0.60. A woman pushes horizontally against the box with a force of 539 N until the box attains a speed of 2 m/s. What is the CM-work done by...
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    Calculating Work and Friction in a Box on a Flat Floor

    Yeah, I didn't use that supposition. I used vf^2 = vo^2 + 2(a) d instead to find distance... I just want to know if my answers for work of the woman and of the friction force are correct?
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    Calculating Work and Friction in a Box on a Flat Floor

    So delta KE is 220.5, work by woman 220.5, and work by the force of friction = (u)mg (d) = .6(9.8)49( 441/1256) = 101.1631... ? Is that right?
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    Calculating Work and Friction in a Box on a Flat Floor

    But that's the KE, they're not the same are they?
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    Calculating Work and Friction in a Box on a Flat Floor

    vf^2 = vo^2 + 2(a) d? seems to be what I'm looking for maybe. Do I use F=ma to splve for a? so 3^2 = 2 (d) 628/49. making d = 441/1256? so W= 628 (441/1256) = 220.5
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    Calculating Work and Friction in a Box on a Flat Floor

    Also CM-work is center of mass right? not centimeter?
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    Calculating Work and Friction in a Box on a Flat Floor

    Homework Statement A box of mass 49 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0.60. A woman pushes horizontally against the box with a force of 628 N until the box attains a speed of 3 m/s. What is the work done by the...