Recent content by Geometry
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Undergrad How do charts on differentiable manifolds have derivatives without a metric?
Math_QED : you can show it without Riemannian structure (in fact you can show the assertions above are equivalent to "##M## is homeomorph to a closed set of ##L^{2}(\mathbb{N})##").End of digression.- Geometry
- Post #10
- Forum: Topology and Analysis
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Undergrad How do charts on differentiable manifolds have derivatives without a metric?
Hello, to answer to the first question, if you've got a topological space ##M## such that any ##x \in M## admit a neighborhood homeomorph to an open space of ##\mathbb{R}^{n}##, then the following assertion are equivalent : a)##M## is an Hausdorff space with a countable basis of open...- Geometry
- Post #7
- Forum: Topology and Analysis
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Undergrad Generalisation of Polarization identity
Hello, This is very clear and very adapted for my needs. Thank you very much WWGD. I wish you a good day.- Geometry
- Post #4
- Forum: Linear and Abstract Algebra
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Undergrad Generalisation of Polarization identity
Their is a a way to developed the formal sum : ##(x_1 + x_2 + ... + x_k)^n## no? It might help but this will create a big sum with a lot of binomial coefficient.- Geometry
- Post #2
- Forum: Linear and Abstract Algebra
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Undergrad Generalisation of Polarization identity
Hello, If I have a quadratic form ##q## on a ##\mathbb{R}## vectorial space ##E##, its associated bilinear symmetric form ##b## can be deduce by the following formula : ##b(., .) = \frac{q(. + .) - q(.) - q(.)}{2}##. So that, an homogeneous polynomial of degree 2 can be associated to a blinear...- Geometry
- Thread
- Identity Polarization
- Replies: 3
- Forum: Linear and Abstract Algebra
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What is the Agrégation and How Does it Relate to Differential Geometry?
Hello, thank you for your warming welcome. Have a nice day.- Geometry
- Post #4
- Forum: New Member Introductions
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Undergrad Proof of ##F## is an orthogonal projection if and only if symmetric
Hi, for the second equality you've got : ##||F(v)||^2 = <v, F(F(v))>## (because ##F## is symmetric) and this equate ##0## since ##v \in Im(F)^{\perp}## and ##F(F(v)) \in Im(F)##. Where is the problem? Perhaps I didn't understand the question.- Geometry
- Post #3
- Forum: Linear and Abstract Algebra
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What is the Agrégation and How Does it Relate to Differential Geometry?
Hello, I'm new here. I'm french and I'm very interest at differential geometry. I came here to ask questions and if I can help other people. My level at school : I achieve (some years ago) a master degree and the agrégation (describtion here : https://en.wikipedia.org/wiki/Agr%C3%A9gation )...- Geometry
- Thread
- Replies: 3
- Forum: New Member Introductions