Homework Statement
1.)I can't get it why a friend of mine from this forum is getting 56.01N and me 56.70N
2.) I got this solution 50Ncos30-(0.02(20(9.8)-50sin30))/20, what did you get??
3.) (0.4(20x9.8))/cos30+(0.4(sin30)) what did you get?
Homework Equations
1)F= (0.1(50x9.8))/(cos25 -...
hey can i ask? what is the Fapp in the formula of acceleration?
and why do I keep getting 56.70N instead of 56.01?
i got this value of 49/0.8641=56.70N
Homework Statement
What is the tension on the traction system??
i was given this picture.. the M= 10kg..
I got this picture,, the traction system is the figure that has a feet hanging.
Homework Equations
T=W=mg
T=W=m2g
The Attempt at a Solution
T=W=10*9.8m/s =98N.
T=W=10(2)...
what did you get?
56.70N?
then for the acceleration the formula is = a=Fappcos/theta-ukFn/m am I right? what nos. did it give you(assuming that u already substituted for their value,, so that I can compare)
and how can I solve for the time?
so the only problem is my first equation?
then the rest 2nd,3rd,4th and Final equations are correct? :)
can you please show me how to compute the time? needed to achieve a 5m/s?
I see.. so is this the right formula?
Fcos/theta-us(fg-Fsin/theta=0
Fcos/theta-usFg+usFsin/theta=0
Fcos/theta+usFsin/theta=usFg
F=us x Fg/cos/theta+ussin/theta
so..
F= (0.1(50x9.8))/cos25+(0.03(sin25))
is that it?
if not.. can you please illustrate the formula to be used for A) B) & C)...
tnx!
so if I am not mistaken.. Fappcos/theta-f=maFn+Fappsin/theta=Fappcos/theta-u..
then..
Fappcos/theta-mukFn=maFn=Fg-Fappsin/theta
that gives me..
a=Fappcos/theta-ukFn/m
am i right?