FORMULA CALCULATION PROBLEM about FORCE

[gianne671]

Homework Statement

1.)I can't get it why a friend of mine from this forum is getting 56.01N and me 56.70N
2.) I got this solution 50Ncos30-(0.02(20(9.8)-50sin30))/20, what did you get??
3.) (0.4(20x9.8))/cos30+(0.4(sin30)) what did you get?

Homework Equations

1)F= (0.1(50x9.8))/(cos25 - (0.1sin25))
2)50Ncos30-(0.02(20(9.8)-50sin30))/20
3) (0.4(20x9.8))/cos30+(0.4(sin30)) what did you get?

The Attempt at a Solution

1)F= (0.1(50x9.8))/(cos25 - (0.1sin25)) =56.70N

and my friend got 56.01N?

2) 50Ncos30-(0.02(20(9.8)-50sin30))/20=1.99m/s^2
3) (0.4(20x9.8))/cos30+(0.4(sin30))= 73.5N

all I'm asking is your answers on this following formula..

 

[Delphi51]

F= (0.1(50x9.8))/(cos25 - (0.1sin25)) =56.70N

I agree.
It would be interesting to try the calc with calculator on radians and see if you get 56.01.

 

[gianne671]

so you agree with me? that my answer is correct?? 56.70N? how about the other equations? what did you get?

 

[I like Serena]

Let's see:
2) 50Ncos30-(0.02(20(9.8)-50sin30))/20 = 43.1
3) (0.4(20x9.8))/cos30+(0.4(sin30)) = 90.7

I see a mismatch...

But, seeing the structure of your formula, I suspect you need:
2) (50Ncos30-0.02(20(9.8)-50sin30))/20 = 1.99