# FORMULA CALCULATION PROBLEM about FORCE

1. Oct 21, 2011

### gianne671

1. The problem statement, all variables and given/known data
1.)I can't get it why a friend of mine from this forum is getting 56.01N and me 56.70N
2.) I got this solution 50Ncos30-(0.02(20(9.8)-50sin30))/20, what did you get??
3.) (0.4(20x9.8))/cos30+(0.4(sin30)) what did you get?
2. Relevant equations
1)F= (0.1(50x9.8))/(cos25 - (0.1sin25))
2)50Ncos30-(0.02(20(9.8)-50sin30))/20
3) (0.4(20x9.8))/cos30+(0.4(sin30)) what did you get?

3. The attempt at a solution
1)F= (0.1(50x9.8))/(cos25 - (0.1sin25)) =56.70N

and my friend got 56.01N???

2) 50Ncos30-(0.02(20(9.8)-50sin30))/20=1.99m/s^2
3) (0.4(20x9.8))/cos30+(0.4(sin30))= 73.5N

2. Oct 21, 2011

### Delphi51

I agree.
It would be interesting to try the calc with calculator on radians and see if you get 56.01.

3. Oct 21, 2011

### gianne671

so you agree with me? that my answer is correct?? 56.70N? how about the other equations? what did you get?

4. Oct 22, 2011

### I like Serena

Let's see:
2) 50Ncos30-(0.02(20(9.8)-50sin30))/20 = 43.1
3) (0.4(20x9.8))/cos30+(0.4(sin30)) = 90.7

I see a mismatch...

But, seeing the structure of your formula, I suspect you need:
2) (50Ncos30-0.02(20(9.8)-50sin30))/20 = 1.99