Recent content by gixx3r

I plugged in 494064 into KE = 1/2 mv^2 494064 = 1/2 (7.35x10^22kg) v^2 v = 3.66x10^-9 Does this sound correct?

Ok, here is what I got using your advice: GPE at the surface: GMm/r = (6.67x10^-11 N m^2/kg^2)(7.35x10^22 kg) / 1.74x10^6 m = 2817500 J GPE at 370km: GMm/r = (6.67x10^-11 N m^2/kg^2)(7.35x10^22kg) / 370000m + 1.74x10^6 m = 2323436 J 2817500 J - 2323436 J = 494064 J = KE Am I...

Thanks for your reply. I tried the equations again and I'm still getting the same answer. It is wrong and I don't understand why :( Based on the conservation of energy equation you mentioned: 1/2mv^2 = mgh 1/2v^2 = gh v^2 = 2gh v = sqroot (2gh) = sqroot [(2)(1.62m/s^2)(370000m)] v =...

Homework Statement A projectile launched vertically from the surface of the Moon rises to an altitude of 370 km. What was the projectile's initial speed? Homework Equations h = 370,000 m g moon = 1.62 m/s^2 G = 6.67x10^-11 N m^2/kg^2 Mass moon = 7.35x10^22 kg Radius moon =...

Homework Statement Let's say you are given 10 identical springs. How would you develop a scale of force (i.e., a means of producing repeatable forces of variety of sizes) using these springs? Homework Equations None that I can think of. The Attempt at a Solution My guess is that...