Recent content by goaliejoe35

Suppose that the system of figure (a) has the input x(t) given in Figure (b). The impulse response is the unit step function h(t) = u(t). Find and sketch the system output y(t). http://qaboard.cramster.com/answer-board/image/a4d35f0d5eef154398161f9124b69a59.jpg...

I don't understand why your subtracting?

Homework Statement Calculate the binary equivalent of 2/3 out to eight places. Then convert from binary to decimal. How close is the result to 2/3? The attempt at a solution I new to this and I am still trying to figure this stuff out so if someone could walk me through this that...

Yea that's the only way I know how. But I'm looking at a different way now where they give you the standard equation y' +P(x)y = Q(x), but I don't quite understand it.

y=C(x-1)^6

Homework Statement Find the particular solution of the differential equation xdy=(x+y-4)dx that satisfies the initial condition y(1)=7 . The attempt at a solution Ok here's my first two steps... dy = \frac{(x+y-4)}{x} dx \frac{dy}{(x+y-4)} = \frac{dx}{x} Now here's where I get messed...

The angle would be 30 degrees? Perpendicular would be sine? Parallel would be cosine?

Look at the attachment it has the two diagrams I drew. I can't seem to put together an equation for it. I haven't done a whole lot of these problems before.

I'm really having trouble trying to set up an equation for this. Can you give me a better idea of how to set it up?

The contact forces would be against each other correct? So those would be in opposite directions in my diagram. How do i figure out what that force is?

Homework Statement A 2.5 kg block and a 3.1 kg block slide down a 30 degree incline. The coefficient of kinetic friction between the 2.5 kg block and the slope is 0.23; between the 3.1 kg block and the slope is 0.51. Determine the (a) acceleration of the pair and (b) force the lighter...

Ohhh my mistake. e^(ln(y))=e^6ln(x-1) y=(x-1)^6 is that correct now?

so it would be.. e^(ln(y))=6e^(ln(x-1)) + C

ln(y)/6 = ln(x-1) + C Now how do I solve for y? I am not sure what to do with the ln's.

ln(y)/6 is that right? and is the other side correct?