Recent content by goodcow
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Undergrad Why is the work done by an ideal gas the area under a PV diagram?
Oh...wow I'm silly. Thanks! -
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Undergrad Understanding 1amu to 931.5MeV/c^2 Conversion: Explained in Simple Terms"
Thank you: I see how it works now- goodcow
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- Forum: High Energy, Nuclear, Particle Physics
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Undergrad Why is the work done by an ideal gas the area under a PV diagram?
Well yes, I know that the equation is true, but I was wondering why it's physically true. For example, the area under a velocity-time graph is displacement. Why is the area under the graph the work done? -
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Undergrad Understanding 1amu to 931.5MeV/c^2 Conversion: Explained in Simple Terms"
Hi, could someone explain why 1amu=931.5MeV/c^2 ? Thanks- goodcow
- Thread
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics
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Undergrad Why is the work done by an ideal gas the area under a PV diagram?
Could someone please prove why the work done by a gas is the area under a PV diagram? That is, I know that dW=P \text{ }dV, but why is that true physically? I realize that W=f \cdot d \text{ and } F=P \cdot A .Thanks. -
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Undergrad How to prove Theta for a incline plane.
If you draw down the lines for force from the point where the box touches the ramp, everything becomes much clearer. Two right angles are created: one at the flat base of the ramp and one at the point where the box touches the ramp. The triangle with the original θ is completed by an angle with...