Recent content by Hebel

B rises by 2h right? Is that because, if one lowers A by h the one part of the rope supporting A needs to gain a length of h and the other part does as well...? I lack experimental experience with this, are there any animations/experiments/resources you know of?

Well the part on the left (supporting A) goes 'up' h and the part on the right 'down' h? So the rope as a whole 2h? :woot:

I updated my question, but I still don't really know how to find a concrete relationship between a vertical height (traversed by pulley) and length of the string?

Hmm that's a good point. I will keep that in mind and apologize for my rudeness. Well I tried using an energy argument: i.e. G.P.E --> K.E., but there are just too many variables, as I don't know the masses of either of the bodies involved etc. Why isn't it just 2h as well? I can't seem to...

Homework Statement (see attached diagram) Homework Equations (see attached diagram) The Attempt at a Solution I drew a diagram.What I know. Left part of rope is fixed to ceiling so extra rope comes 'from the right' i.e. 'falls down' as pulley is pulled. I also know that rope is conserved.

So the new area is 4 times the old one I see, so we are just assuming that the area of the beam incident on the screen will be circular right?

Why does twice the width mean 4 times the area?

Homework Statement (see attached problem) Homework Equations (see attached problem) The Attempt at a Solution So assuming the area of the hole is circular, halving its diameter, will decrease its area by a factor of 16. Therefore LI will be I/16? However in the solution (see attached...