Recent content by HRG

Tom.G, Baluncore, Filip Larsen, Jack action and Baluncore, Thank your for your responses. Appears that the method works, though it still seems mind boggling

I watched workers install a guy wire to support a telephone pole today. The method used was a single guy wire that just had the two legs of the stay wire wrapped around the single guy wire and that' it. Why won't the guy wire just be pulled out from the stay wires? To illustrate, see 1:08 in...

The tongue weight is established statically, not dynamically. For a small trailer and boat like mine, one method is to have the trailer level and support the hitch ball receiver on a bathroom scale. The static weight needs to be 10-15% of the total weight of trailer, boat and contents. Not...

anuttarasammyak and Orodruin, Thank you for your replies. ... How could we possibly answer that if you do not show us your calculation and assumptions? ... I thought that folks would do the calculation using their own method and let me know if the result agreed with mine. Here's my...

New trailer and new self built boat. Need confirmation of my calculation for placement of boat on trailer to have the correct tongue weight. For those not familiar with trailers: The tongue of a trailer is the forward beam that has the female ball receiver at the front end. It is imperative...

I need to tighten the nut for a trailer hitch ball to 250 ft lbs but I don't have a torque wrench that can do it. I read on a different forum that an alternate old school method to get 450 ft lbs of torque is: Torque = Force x Distance So in that forum's example, have a 180 lb person stand on...

I was wanting to know about how many inches the back of the boat might sink down. But yes, I could have used feet and converted the answer to inches at the end. Glad to see that my answer matches yours though. Thanks.

Here's my calculations: 1 cu ft = 1728 cu inches, 1 cu ft of sea water weighs 64 lbs. x cu in/373 lbs = 1728 cu in/64 lbs. x = 10071 cu inches. volume of a right angle wedge = 10071 cu inches (area of a right triangle) width of boat = 10071 (short leg of right triangle x long leg / 2) 48" =...

Bingo. That is exactly the angle that I calculated using 373 lbs. 2.6 degrees. Thanks!

My calculation with just the 55lb motor was .996 inches for the right triangle's short side. Ended up with 0.6 degrees tilt. I'm recalculating with 373 lbs on the back of the boat. Thanks.

Please just assume that the 373 lbs is 1 foot from the back of the boat. I just want to know the "approximate" angle the top of the boat will be relative to the surface of the water. I'll post my answer when I recalculate it and see if others come up with approximately the same angle. Thanks.

Since the boat will be perfectly level with nothing in it, please disregard the weight of the boat. I did add the weight of the gas and 2 adults in my original post. Just assume that all of that weight is concentrated about 1 foot from the back end of the boat. I just need the "approximate"...

I want to calculate the angle of a wooden boat at rest in salt water, with a 55 lb outboard motor mounted on the transom + 3 gallons of gasoline (18 lbs) + 2 adults weighing about 150 lbs each. So just figure a total weight at the back end of the boat being 55 + 18 + 300 = 373 lbs. The boat...

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Wow, way more complex than what I have in mind. But I appreciate your contribution to my question. Thanks.