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I want to calculate the angle of a wooden boat at rest in salt water, with a 55 lb outboard motor mounted on the transom + 3 gallons of gasoline (18 lbs) + 2 adults weighing about 150 lbs each. So just figure a total weight at the back end of the boat being 55 + 18 + 300 = 373 lbs.

The boat will be a jon boat that has a flat bottom. It will be 4 feet wide x 12 feet long. Assume that the part of the boat that is "in the water" is a rectangular box that is 4 feet wide x 8 feet long. The 4 feet to the bow plate is curved upward so will not be in the water. So for the calculation, just figure a 4' x 8' rectangular box with 373 lbs on one end.

For info, so you don't have to look it up, one cubic feet of sea water weighs approximately 64 lbs.

What will be the angle of the top of the boat relative to the surface of the water, when the boat is at rest in the water? (The top and bottom of the boat are parallel)

EDIT: I came up with an angle of 2.6 degrees.

The boat will be a jon boat that has a flat bottom. It will be 4 feet wide x 12 feet long. Assume that the part of the boat that is "in the water" is a rectangular box that is 4 feet wide x 8 feet long. The 4 feet to the bow plate is curved upward so will not be in the water. So for the calculation, just figure a 4' x 8' rectangular box with 373 lbs on one end.

For info, so you don't have to look it up, one cubic feet of sea water weighs approximately 64 lbs.

What will be the angle of the top of the boat relative to the surface of the water, when the boat is at rest in the water? (The top and bottom of the boat are parallel)

EDIT: I came up with an angle of 2.6 degrees.

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