Recent content by Illuvitar

Ill talk to my professor about it, like I said he has made some mistakes before because english is not his first language. Hopefully I will get partial credit even though the problem doesn't make sense. Thank you so much for helping me through it though, I was very confused.

My professor writes out our homework problem sets but it is g not kg. This has kinda happened before. On our first test he gave everyone 10 points because he messed up the units and phrasing on two of the questions.

the originally mass of the sample was 0.0293g Fe. So am I supposed to divide the actual by the theoretical yield and multiply by 100% to get the mass percentage?

Okay so in 13.25 ml of a .200 M stannous there are 2.65x10-3 moles. So I convert moles SnCl to moles Fe to grams Fe? 2.65x10-3moles SnCl2 x 2 moles Fe/1 mol SnCl2 x 55.85g Fe/1 mole Fe to end up with 0.296 grams Fe? So this is 29.6% of the mass of Fe? Is this what I am looking for?

Algebra 2 :/

Why are there 1/2 mole Fe for every 1 mole of stannous if the balanced equation is : 2 Fe3+(aq) + Sn2+(aq) ⇒2Fe2+(aq)+Sn4+ ? So I am trying to find grams of Fe? And yes I I am blindly trying to apply dimensional analysis to this problem because I don't understand what to do. There are no...

Im sorry I am such an idiot for not understanding...but I just don't understand this problem, I am even more confused now. Thank you so much for your patience.

Well mol/L is the mass percent of a solution right? I am guessing this is wrong. Yeah I tried to use this to represent a dimensional analysis chain : 2.65x10-3 moles SnCl2 x 2 mol Fe3+/1mol SnCl2 x 55.85g Fe3+/1 mol Fe3+...

Yes the problem I am having is utilizing this relationship in dimensional analysis to end with the units I am looking for. Here is one of the strategies I have come up with (the main problem I am having is fitting in the 0.0293g Fe3+ ) 2.65x10-3 moles SnCl2 x 2 mol Fe3+/1mol...

Chet Oh sorry, moles of stannous chloride.

Thanks for the response. It gives me the information about the number of moles contained in 13.25 ml solution. 2.65x10-3 moles. I've tried to use this: 13.25ml x 1L/103ml x.200mole SnCl2/ 1 L but I keep having trouble ending up with mol/L to find the molarity of Fe3+. Ill keep trying to play...

Its 13.25 ml of stannous chloride solution which contains 0.200 moles per liter. It is the amount of solution that is required to completely react with 0.0293g Fe3+.

Hello, I am in desperate need of help with setting up this problem and I would very much appreciate being steered in the right direction. 1. Homework Statement Find the mass percent of Fe3+ in a 0.0293g sample of iron ore if 13.25 ml of a .200 M stannous chloride solution is required to...

Alright sorry...

If I move them to one side I get ##log(4x/x+4)=0## because of the quotient property right? but I don't know how to simplify it further. And I am not sure I understand how I should use ##a^0=1## its seems like the terms have an implied power of 1.