Recent content by imselva

  1. imselva

    Coefficient of Thermal conductivity

    If it is not constant, how to calculate it analytically? Is there any other relation to calculate Q
  2. imselva

    Coefficient of Thermal conductivity

    We know that, Conduction Heat Transfer Q = KA(t2-t1)/thickness K is the coefficient of thermal conductivity. If T2 = 1020°C and T1= 22°C also consider we know A and thickness value. K depends on temperature. K varies with temperature. For all the materials we have a tabular data of K for...
  3. imselva

    Conduction heat transfer with varying cross section

    Q1 = (-K*A1*(1020-T))/d1 Q2 = (-K*A2*(T-20))/d2
  4. imselva

    Conduction heat transfer with varying cross section

    The temperature T1 at the top Surface is 1020°C and T2 at the Bottom Surface is 20°C and K is the thermal conductivity of the material. What is the conduction heat Transfer Q. ?
  5. imselva

    Conduction heat transfer with varying cross section

    The geomentry consists of two parts in complete contact with each other. The first part is a Stadium shape with 5 mm thickness and a height of 39.4mm. The second part is also Stadium shape with 0.9mm thickness and a height of 64.8mm. The Bottom of the first part is at 1020°C and the top for...
  6. imselva

    Conduction heat transfer with varying cross section

    How to modify this Formula? and arrive at the solution. Q = -K(Th-Tc)A/thickness
  7. imselva

    Radiation heat transfer using 12 heat sources

    So can I proceed by adding the intensity contribution from multiple sources? In the example I quoted in the previous Reply, the intensity at Point 1 is the sum of 46,25 and 12 i.e. 83. Not just 46. Is there any kind of basic physics behind this addition of intensity. So that I could study more...
  8. imselva

    Radiation heat transfer using 12 heat sources

    This is how I stared the Problem. I took the flat Surface on the left side and placed 20 Points on ist Surface. Also I took the top curved Surface and placed 20 Points on it. I calculated the angle of incidence for all the considered Points on the Surface. I already took into account the...
  9. imselva

    Radiation heat transfer using 12 heat sources

    The heat Sources can be moved (Maximum distance between the wall and the heat source is 80mm). I ran the calculations in MATLAB by varaying the distance between the Radiators and the muffle. The heat source is a cylinder of 19mm Diameter. The whole set up is completely insulated and there is...
  10. imselva

    Radiation heat transfer using 12 heat sources

    Yes that is the usual approach. But due to some constraints I have to stick with this. The intensity of the heat flux from the Sources varies with the angle of incidence. To my understanding and knowledge if a Point on the work volume if getting heat flux from 2 sources, say A and B. Say the...
  11. imselva

    Radiation heat transfer using 12 heat sources

    Sorry that I did not mention that. I am trying to move the heating Elements around the "Muffle chamber"(Yes it is a furnace in a Simulator used to heat the specimen) so that I get the same intensity of Radiation at all Points on the muffle chamber. GOAL : To achieve same intensity on all...
  12. imselva

    Radiation heat transfer using 12 heat sources

    The intensity is proportional to the square of the distance between the source and the body and also depends on the angle of incident. I = The intensity at 0° (Assuming I = some constant) then I0 = I cos(Theta) Theta = the angle of incidence. I want to solve this using trignomentry. Is it...
  13. imselva

    What is the Equilibrium State in Radiation Heat Transfer?

    I have two bodies, one at a higher temperature say 1000°C (Body A) and the other is at 22°C (Body B). Body A emits Radiation (Surface to Surface interaction). The temperature of Body A is maintained by a constant supply of Energy. The Body B will absorb the Radiation Energy from Body A, and its...
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