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Summary:

The thickness of the 39.4mm part is 5mm and the thickness of 64.8 mm part is.
The temperature on the top cross sectional Surface is 1020°C and 20°C on the Bottom cross sectional surface.
If K is the thermal conductivity of the material. T1 and T2 are hot and Cold temp. A1 and A2 are the cross sectional Areas. What is the conduction heat Transfer Q?
How to modify this Formula? and arrive at the solution.
Q = K(ThTc)A/thickness