- #1
imselva
- 14
- 0
How to modify this Formula? and arrive at the solution.
Q = -K(Th-Tc)A/thickness
Conduction heat transfer with varying cross section
- Context: Undergrad
- Thread starter imselva
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Discussion Overview
The discussion revolves around the calculation of conduction heat transfer between two parts with varying cross-sections and different temperatures. Participants explore the application of heat conduction formulas in a specific geometric configuration involving two stadium-shaped components in contact.
Discussion Character
- Technical explanation
- Mathematical reasoning
Main Points Raised
- One participant seeks to modify the heat conduction formula Q = -K(Th-Tc)A/thickness to fit their specific scenario.
- Another participant expresses confusion regarding the geometry of the system being described.
- A participant describes the geometry, detailing two stadium-shaped parts with specified thicknesses and heights, along with their respective temperatures.
- There is a clarification about the temperatures at the surfaces of the two parts, with one at 1020°C and the other at 20°C.
- One participant introduces the concept of a junction temperature T, suggesting that heat transfer Q will be consistent through both parts and asks for the heat conduction equations for each part in terms of T.
- Equations for heat transfer Q1 and Q2 are presented, indicating the relationship between the junction temperature T and the heat transfer through each part.
- Participants reiterate the equations for Q1 and Q2 and suggest eliminating T between the two equations to find a solution.
Areas of Agreement / Disagreement
Participants appear to be exploring the problem collaboratively, with some agreement on the need to establish equations for heat transfer. However, there is no consensus on the final solution or the method to eliminate T from the equations.
Contextual Notes
The discussion does not resolve the assumptions regarding the thermal conductivity K or the specific areas A1 and A2, which are necessary for completing the calculations.
How to modify this Formula? and arrive at the solution.
Q = -K(Th-Tc)A/thickness
- #2
- 23,721
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I don't understand the geometry you are trying to specify.
- #3
imselva
- 14
- 0
The geomentry consists of two parts in complete contact with each other.
The first part is a Stadium shape with 5 mm thickness and a height of 39.4mm.
The second part is also Stadium shape with 0.9mm thickness and a height of 64.8mm.
The Bottom of the first part is at 1020°C and the top for the second part is 20°C.
I want to calculate the conduction heat Transfer between the two different temperatures. How to find Q?
The first part is a Stadium shape with 5 mm thickness and a height of 39.4mm.
The second part is also Stadium shape with 0.9mm thickness and a height of 64.8mm.
The Bottom of the first part is at 1020°C and the top for the second part is 20°C.
I want to calculate the conduction heat Transfer between the two different temperatures. How to find Q?
- #4
imselva
- 14
- 0
View attachment Unbenannt.PNGThe temperature T1 at the top Surface is 1020°C and T2 at the Bottom Surface is 20°C and K is the thermal conductivity of the material.
What is the conduction heat Transfer Q. ?
What is the conduction heat Transfer Q. ?
- #5
- 23,721
- 5,934
Let T be the temperature at the junction between the two parts. Q is going to be the same through each of the two parts. In terms of T, what are the two heat conduction equations for each of the two parts?
- #6
imselva
- 14
- 0
Q1 = (-K*A1*(1020-T))/d1
Q2 = (-K*A2*(T-20))/d2
Q2 = (-K*A2*(T-20))/d2
- #7
- 23,721
- 5,934
Q1 and Q2 are both Q. Eliminate T between the two equations.imselva said:
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