Recent content by Innuendo

thank you

I'm trying to find the derivative of 0 = 3xcosƟ with respect to time. I know I should use the product rule for x and cosƟ. But I don't know what I should do with the constant 3. would it be like this? 0 = 3x(-sinƟ)(dƟ/dt) + 3(dx/dt)(cosƟ)

I split the force pushing the block up the incline into two forces on the x-y coordinates, so Fx and Fy. I'm confused on whether Fx . d does any work since it is normal to the gravity. I assumed that the gravity is the only source that creates work for the F because Fy is acting parallel to the...

A block is pushed up an incline over a distance. Now I have to find the work in the system, so my question is, does work only exist in the y direction? Is there work in the x direction of the force while pushing up the incline?

ahh thank you

So I should carry the t in the force and set a(t) = F(t) / m ? a(t) = t / 5 v(t) = t^2 / 10 v(10) = 10 m/s?

Homework Statement A force of F(t) = t is pushing a block of 5kg mass with no friction. What is the velocity after 10 seconds? Homework Equations F=ma The Attempt at a Solution F(10) = 10 N a = F/m = 10/5 = 2 m/s^2 a = dv/dt v(t) = 2t v(10) = 20 m/s I've...

\frac{\mid 1 - 1.212226 \mid}{1} \times 100\% = 22.26\%

50 years from now, that car in the picture will seem to us now just like a 10mb harddrive from the 80s.

ohh wow, that works too. thanks.

\frac{\mid 12.34 - 12\frac{1}{3} \mid}{12\frac{1}{3}} \times 100\% = 0.054\%

\frac{12.34 - 12.33}{12.33} x 100 = 0.054

oh wow orbital, that link's great. just what I needed.

ohh thank you.

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