Does Work in an Inclined System Only Occur in the Y Direction?

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SUMMARY

The discussion centers on the concept of work in physics, specifically in the context of a block being pushed up an incline. Work is defined as the product of displacement along the direction of the force and the magnitude of the force applied. The participants clarify that work is a scalar quantity and can be analyzed using vector components, specifically separating the force into x and y components (Fx and Fy). It is concluded that while Fy contributes to the work done against gravity, Fx does not perform work in this scenario as it is perpendicular to the direction of gravitational force.

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A block is pushed up an incline over a distance.

Now I have to find the work in the system, so my question is, does work only exist in the y direction? Is there work in the x direction of the force while pushing up the incline?
 
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What is work?

It is the product of the displacement along the direction of the force with the magnitude of the force applied

Vectorially work is (for constant force) F.s where [.] means dot product of the F vector and s vector

If F is not constant then W = integral of F.ds

Work is a scalar: So how can work exist in x-direction or y-direction?
 
I split the force pushing the block up the incline into two forces on the x-y coordinates, so Fx and Fy. I'm confused on whether Fx . d does any work since it is normal to the gravity. I assumed that the gravity is the only source that creates work for the F because Fy is acting parallel to the gravity, and so work is done, for the Fy component of F.
 

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