Recent content by itzik26
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Graduate STM experiment (HOPG) data analysis/image processing
it really looks good, doesn't it?? I got really excited :) do you know how can I do this cut-off in matlab?- itzik26
- Post #3
- Forum: Atomic and Condensed Matter
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Graduate STM experiment (HOPG) data analysis/image processing
hi, I've got a really great picture of the carbon atoms in a graphine (HOPG) sample, using STM technique (picture attached). I would like to remove from the picture all the data came from noise etc.. I'm working with MATLAB, and I tried to use fast Fourier transform (fft2), but didn't know how...- itzik26
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- Data Experiment Processing Stm
- Replies: 3
- Forum: Atomic and Condensed Matter
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Graduate Lipschitz function and Baire Category Theorem
it's not Lipschitz because it's first derivative isn't bounded close to 0. o.k., so given f and a>0, define g as follows: g=sqrt[x-r] in the interval [r,a^2/4+r], g=0 for x<=r and g=a/2 for x>=a^2/4+r. g is not Lipschitz on [r,s]. define h=f+g. h isn't Lipschitz because g isn't Lipschitz and...- itzik26
- Post #5
- Forum: Topology and Analysis
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Graduate Lipschitz function and Baire Category Theorem
sqrt(x), for example, is continuous but not lipschitz on [0,1], but i don't know how to continue from here.- itzik26
- Post #3
- Forum: Topology and Analysis
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Graduate Lipschitz function and Baire Category Theorem
hey, I need to show, using Baire Category Theorem, that there exits a continuous function f: [0,1] to R , that isn't Lipschitz on the interval [r,s] for every 0<=r<s<=1 . I defined the set A(r,s) to be all the continuous functions that are lipschitz on the interval [r,s]. I showed that...- itzik26
- Thread
- Function Lipschitz Theorem
- Replies: 4
- Forum: Topology and Analysis
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Graduate Is There a Nowhere Dense Continuous Function on [0,1]?
hey, I need to show, using Baire Category Theorem, that there exits a continuous function f: [0,1] to R , that isn't Lipschitz on the interval [r,s] for every 0<=r<s<=1 . I defined the set A(r,s) to be all the continuous functions that are lipschitz on the interval [r,s]. I showed that...