I just have a concept question on LCP.
in reaction: A(aq) + B(aq) <-> C(aq)
A is added and rxn is left to reach a new equilibrium.
Once @ new eqm, is [A] higher than before? and obviously [C] is lower, right?
oh my gosh, that's so funny! I thought my chemistry teacher was evil enough to give us a question that had a negative answer :)
Well, solubility of Silver Chromate is 1.1x10-12, so I guess the question had it right.
But how do you know that 2.0x10-4 M solution doesn't exist?
(ps: I don't...
Hmm.. concentration of CrO4 comes from Na2CrO4...
Well, I used algebra to find the initial concentration of CrO4, and ended up with a negative value.
Here's what I did:
I declared x as [CrO4]init,
so [CrO4] @ eqb = 1.0x10-4 + x
Since Ksp = [Ag]^2[CrO4],
[CrO4] (at eqb?) = 1.1x10-12 /...
When 50.0 mL of a 2.0 × 10-4 M Ag2CrO4 solution was added to 50.0 mL of a Na2CrO4 solution a ppt formed (Ag2Cro4). What was the initial concentration of this Na2CrO4 solution?
Ksp Ag2CrO4 = 1.1 × 10-12
Given A2 (aq) + B(aq) -> AB(s)
Ksp = [A]n[B]
Ahh,, I see your point! :)
However, there's still a problem of finding voy or vfy...
I can't put any of these two as zero, since there is the initial "kick" to the ball, which means at the bottom of its parabolic shape (above the 2.0m height), its v is not going to be zero...
Any idea? :P
You mean v^2 = vo^2 + 2ad?
d=vot + 1/2 (at^2)
Even if I were to use either one, I can't solve vf or vo for vertical, since I do not have dy (it would be bigger than 2.0m, because it moves up first)
I am also not given the vo....
thanks for the quick reply, though :)
A person kicks a ball h of 2.0 m above the floor. If the ball flies at some angle and lands 1.2 s later at horiz d of 6.5 m from its orig. place, calc. the orig. horiz and vert. comp.s of the ball's v.
Calc. the final components of the ball's v.
(Assume the ball has no horiz...