Recent content by jae05

Homework Statement A solar cell has a current–voltage characteristic given by I=I_0\cos\(\frac{\pi V}{2V_0}\) where I_0 and V_0 are given constants. If the sun shines 12 out of 24 hours what is the maximum energy that can the cell can deliver to a load per year? Homework Equations P=IV...

well, most other kinds of thermometers have a specific range, outside of which they would be inaccurate. i think the question just wants to show that const vol thermometers are accurate over a wide range. anyhow, i did some googling and came up with this...

isn't \sin{\frac{kx}{x}}=\sin{k}? do you mean {\frac{\sin{kx}}{x}} instead?

why are they clearly different? i don't seem to get you. it looks like there's ma on one side, and a sum of forces on the other side. looks perfectly like the 2nd law to me. is it the H(t) term you're worrying about?

the picture link that kalvin posted... courses.science.fau.edu/~rjordan/busters_22/1.14q.gif i mean as far as i know, rubbing the comb gathers static charge on the comb, which then attracts the water flow. and i was just trying to explain the v x B thing, i didn't mean the electron wasn't...

isn't that what i said? maybe i should have quoted kalvin's post. i was referring to his image, not the wiki stuff.

it means just leave Q in your answer. you've already got it

that picture represents static electricity right? that means it's an E-field rather than a B-field. anyway, for the electron to be affected by the B-field, the electron needs to be moving perpendicular to the B-field, as given by the Lorentz force law, F = q (E + v x B). if the quantity v is...

the equation for torque is \tau=I\alpha, and for a disk rotating about its axis, I=\frac{1}{2}MR^2. i think that should solve your problem. cheers

have you tried thinking of the thing as a carnot engine?

well say we have the system at rest, then Mg=kx_0, so say now we define our equilibrium point to be L+x_0 where x_0 is the initial extension, and L is the natural length. introducing a small displacement, the spring will then oscillate about L+x_0 under the restoring force -kx. then we see that...

ok 2nd question first. when the plane hits the barge, not all the plane's momentum is transferred to the barge straight away. it's not an instantaneous effect. the physics you have effectively done with the momentum conservation, is the plane crashing into the deck. taking the initial speed of...

M is the mass of the object that is creating the gravitational potential. so if you want to calculate the potential around the earth, use the the mass of the earth. if you want to calculate the potential around the moon, use the mass of the moon.

yea. that's given by N3L. but it's much more conveinent to think in terms of F_{fric}=\mu N. calculating the entire shift of the Earth everything we want to do a frictional problem's a bit of a stretch :D

Try either using a test mass for Newton's Law of Universal Gravitation to find a location where the net force is zero, or try summing the gravitational potentials such that they be zero. \phi=\frac{GM}{R}