Recent content by jangchen

Oh, I thought current divider was also applied to the inductor. Thank you for your help!

Thank you for your advise! I got what is a steady state right away.

I apologize using English fluently because I am not an Enlgish speaker. When I tried to solve this problem, I used current divider rule. So, $$i_o(t) = \frac{3}{3+5}*4e^{-2t} = 1.5*e^{-2t} A$$ However, This was wrong. The answer is $$ 1.5*e^{-2t} + 0.5 A$$ If I use $$V_O = L*\frac{di}{dt}$$...

wow I understand it thank you!

Thank you for your answer!

I am not an English speaker, I apologize that I cannot use English well. I have a question calculating the IN. When the terminal a-b is short-circuited, is it right that the currents are zero at 2 ohm and 6 ohm resistances?(Because they are parallel with a short-circuit.) Also, because the...

Firstly, I am not a English speaker. So I apologize that I cannot use English well.. I got a), c), e) a) at 0.5cm, E = -q/(2e_0*A) - Q/(2e_0*A) + q/(2e_0*A) = -1.4*10^7 V/m c) at 1.5 cm, E = 0 (inside electrode) e) at 2.5cm, E = -q/(2e_0*A) + Q/(2e_0*A) + q/(2e_0*A) = 1.4*10^7 V/m And I am...

Now I understand surely. Thank you!

Oh, I used 4πr2.. Do I have to use 2πr2 ?

I is proportionate to E. r = 4.3xxm So I put 0.75I The answer is 49mW.. But I got 97.xxmW What is wrong?

Oh not 21/12 but 21/12 The answer is 19m/s... I tried what you taught.. but i got 9.97xxx m/s..

I don't know what is wrong i think when bat gets sound f' = f×(c+v/c) when audience hears f''=f'×(c/c-v) f''=f×1.059 but it is wrong TT