The figure is an edge view of three charged metal electrodes. Let the left electrode be the zero point of the electric potential. Assume that Q=100 nC and q=50 nC.
The left electrode has a charge of -q, the middle electrode has a charge of +Q, and the right electrode has a charge of -q. There is 1 cm in between the left electrode, the middle electrode is 1 cm wide, and there is 1 cm between the middle electrode and the right electrode. All of the electrodes have 2.0 cm x 2.0 cm cross section. I apologize for the lack of a visual, I realize this would make it easier.
a.) What are E at 0.5 cm
b.) What are V at 0.5 cm
c.) What are E at 1.5 cm
d.) What are V at 1.5 cm
e.) What are E at 2.5 cm
f.) What are V at 2.5 cm
Firstly, I am not a English speaker. So I apologize that I cannot use English well..
I got a), c), e)
at 0.5cm, E = -q/(2e_0*A) - Q/(2e_0*A) + q/(2e_0*A) = -1.4*10^7 V/m
at 1.5 cm, E = 0 (inside electrode)
at 2.5cm, E = -q/(2e_0*A) + Q/(2e_0*A) + q/(2e_0*A) = 1.4*10^7 V/m
And I am confused when calculating below..
I got b), f)
at 0.5cm, V = E*d = 1.4*10^7 * 0.005 = 7*10^4 V
at 2.5cm, V = E*d = 1.4*10^7 * 0.005 = 7*10^4 V
Are they right?
And, I don't know how to get the d) answer..
I think V = 0, because E = 0. Is it right?