- #1
jangchen
- 12
- 3
- Homework Statement
- In the circuit of Fig. 63.82 io(0)=2mA. Determine io(t) and Vo(t) for t>0
- Relevant Equations
- $$V_O = L*\frac{di}{dt}$$
When I tried to solve this problem, I used current divider rule.
So, $$i_o(t) = \frac{3}{3+5}*4e^{-2t} = 1.5*e^{-2t} A$$
However, This was wrong.
The answer is $$ 1.5*e^{-2t} + 0.5 A$$
If I use $$V_O = L*\frac{di}{dt}$$ , I can get right answer.
I wonder why there is a difference
between using current divider rule and using $$V_O = L*\frac{di}{dt}$$.