Recent content by Janiceleong26

Thanks

Hi @Chestermiller, I am having some doubts on the temperature of the first evaporator. Assuming the temperature of the first evaporator is the same as the boiling temperature of the NaOH solution.. Is the temperature of the first evaporator equals to the boiling temperature of stream F or F1...

Sry one more thing.. how do we know the boiling point of water at 10w/w% NaOH solution?

Oh I see, okay thanks so much!

I thought the steam provides heat to the evaporator to heat the NaOH solution? So the temperature of the condensate is not the same as V1?

I just realized that I can get the specific enthalpy of stream S at 3.5 bar, by interpolating from 3.4 bar to 3.6 bar from from this table: Table1: Properties of saturated steam: Pressure table For stream F, I can obtain the specific enthalpy from these charts: Chart1: Enthalpy of NaOH solution...

Homework Statement Homework EquationsThe Attempt at a Solution I have identified that only the specific enthalpy for stream F can be found from literature values, whereas the specific enthalpy of other streams are unknowns. The specific enthalpy of streams S, V1, C1, C2 and V2 are unknowns...

Ok got it. Thanks!

I see. Meaning there will be a total of 140 tubes in the heat exchanger? But wouldn't that be 140 tube passes? I'm confused as to what is the difference between 'tube pass' and 'tube'

Homework Statement 'A shell and tube exchanger is used to do heating, with single shell and 2 tube passes. There are 70 tubes each with an outside diameter of 25mm and length of each tube pass is 6m. ' I am wondering whether the 70 tubes are in between the 2 tube passes, or is it 1 tube pass...

So basically force is the gradient of EPE graph, right? Thanks, I think I've got it

(Field x charge)= (potential x charge) / distance We can't straght away say that force is gradient of EPE, because that isn't by definition, is it?

Erm, not really.. 1) Froce on Q is proportional to field strength of P 2) Potential gradient is proportional to gradient of EPE 3) so force is proportional to the gradient of EPE why can't I just straight away write : 1+3) Froce on Q is the gradientof EPE

Oh, that's ok. First pair = Second pair x test charge

Ok, got it, thanks very much!