# Recent content by Jason-Li

1. ### Comp Sci Laplace Transform of the input portion of this circuit

So I have completed (a) as this (original on the left): I have then went onto (b) and I have equated T(s)=Z(s) as follows: and due to hence Does this look correct to you smarter people? Thanks in advance!! All replies are welcome :)
2. ### Comp Sci Fourier analysis & determination of Fourier Series

I am assuming that it would repeat? There is no symmetry that I can see? It would be odd if there was no 'missing' parts of the wave however Thanks for the reply
3. ### Principal frequencies of a Waveform

Hi HDG, Did you get the question correct? I got a final answer also of 97.271% How did you select the fields to create the scattergraph? Thanks for any help!
4. ### Comp Sci Fourier analysis & determination of Fourier Series

ANY AND ALL HELP IS GREATLY APPRECIATED :smile: I have found old posts for this question however after reading through them several times I am having a hard time knowing where to start. I am happy with the sketch that the function is correctly drawn and is neither odd nor even. It's title is...
5. ### Transmission Line Coefficients & Definitions

Hi again Rudeman, Was looking over my old working and found that in the final line of working is incorrect, unless I'm just being an idiot! = √ (31491.630+j9511.802) = 179.427+j26.506Ω Just to update this post.
6. ### Fourier Analysis and the Significance of Odd and Even Functions

@FactChecker I think you give the materials too much credit, time and again I find inconsistencies or incorrect parts. Thanks for your help, it is much appreciated!
7. ### Fourier Analysis and the Significance of Odd and Even Functions

@FactChecker Yeah in the materials the first graph is even (FIG.1) and the second graph (FIG.2) which is FIG.1 'shifted' is now odd, however I would say that it is neither odd nor even, unless as you say it is shifted down the 'Y' axis. There is however no mention of this Y-axis shift in these...
8. ### Fourier Analysis and the Significance of Odd and Even Functions

Hi @bobob thanks for the help that really clears things up! I have tried bulking out the answer for each as follows, does that look correct to you? ( I realise this just builds on what you wrote ) a) Function is neither odd nor even. a0= V/2, an=0 b) Function is even hence will only...
9. ### Fourier Analysis and the Significance of Odd and Even Functions

I thought it wasn't odd, the learning materials seem to be incorrect, it is implying that the diagram shown is odd - seems to be a recurring theme with this learning materials!
10. ### Fourier Analysis and the Significance of Odd and Even Functions

@FactChecker Thanks a lot for the insight, not sure how I messed up the A0 figure. I have one query regarding a similar waveform in the learning materials that has been 'shifted odd' and I am unsure how this wave is 'odd' and not neither? wondering if you can give some insight. Thanks again.
11. ### Fourier Analysis and the Significance of Odd and Even Functions

Ah I see what you mean I think, so I could maybe say the following: - The wave is neither odd nor even - a0 =0 & an = 0 Surely that can't be all there is?
12. ### Fourier Analysis and the Significance of Odd and Even Functions

@Connorm1 Hi all, having a look at this now and I am on the same boat as you were - I don't know how much detail they want and where to start with part (b). I see that you were trying to move the wave down the Y-axis to make it Odd, why not shift it to the right by T/4 so that it creates an...
13. ### Transmission Line Coefficients

Hi Babadag, I would've likely said the same however in my learning materials the below is stipulated. I then equated that each as appropriate. Any ideas?
14. ### Transmission Line Coefficients

Homework Statement Figure shows a 50 Hz, high-voltage, transmission line. The relationships between the sending and receiving end voltages and currents are given by the complex ABCD equations: where 'S' stands for sending-end and 'R' stands for receiving-end (a) Given the parameter values...
15. ### Insertion Loss of a T-Network

I'm trying to do this but can't seem to work it without a value for the voltage source. So i made the three nodes at the top V1, V2 & V3 and made the following equations V2/13 - V3/13 - V3/100 = 0 V2/13 - V1/13 - V1/75 = 0 V1/13 + V3/13 - V2/213 - 2*V2/13 = 0 Struggling to move on from...