Recent content by jbow615

Ok I finally figured it out last night. Thank you guys for your help.

Friction force=(mu)(n). N=mg=(12)(9.8)=(117.6)(.23)=27.048 Work done by friction=(27.048)(4)=108.942 And I forgot this part of the question: 4 forces act on a crate on a friction less surface. Force 1 acts due east at 10 N, force 2 at at angle 50 degrees above the horizontal towards the east...

Help Again Please -- Box sliding on a floor Homework Statement If the friction coefficient between the box and the floor is .23, and the box has a mass of 12 kg, and the magnitude of all four forces is 10 N, what is the change in kinetic energy of the box after it has traveled a distance of...

Help Please -- Ball swinging from a rope Homework Statement A ball of mass 30 kg is hanging from a rope of 3 meter tied to the roof of a truck. The truck is moving at a constant speed of 29.6 m/s. As you look forward at the ball hanging from the roof of the truck, you see the ball hanging...