Recent content by jenny Downer

  1. J

    Proving the Binomial Theorem: Simplifying 3^k C(n,k) = 2^2n

    Use the Binomial Theorem to show that n summation k-0 3^k C(n,k) = 2^2n hint of the question is 3^k C(n,k) = 3^k 1^n-k C(n,k)
  2. J

    Using the Binomial Theorem to Show 3^k C(n,k) = 3^k 1^n-k C(n,k)

    It should be n sum 3^k C(n,k) = 2^2n k=0 the hint is 3^k C(n,k) = 3^k 1^n-k C(n,k)
  3. J

    Using the Binomial Theorem to Show 3^k C(n,k) = 3^k 1^n-k C(n,k)

    i wanted to explain a bit more
  4. J

    Using the Binomial Theorem to Show 3^k C(n,k) = 3^k 1^n-k C(n,k)

    how do i use binomial to show that 3^k C(n,k) = 3^k 1^n-k C(n,k)
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