Using the Binomial Theorem to Show 3^k C(n,k) = 3^k 1^n-k C(n,k)

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Homework Help Overview

The discussion revolves around using the Binomial Theorem to demonstrate a relationship involving binomial coefficients and powers of 3 and 1. The original poster seeks clarification on how to manipulate the expression involving C(n, k) and the powers of 3 and 1.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between binomial coefficients and powers, questioning the correctness of the original expression. Some participants suggest examining the coefficients in a binomial expansion context, while others seek to clarify the intended manipulation of the terms.

Discussion Status

The discussion is ongoing, with participants providing hints and exploring various interpretations of the problem. There is an emphasis on understanding the role of binomial coefficients in the context of the Binomial Theorem.

Contextual Notes

Some participants note potential issues with the original expression, suggesting that it may not be correctly formulated. There is also mention of a specific sum involving powers and binomial coefficients that may need further exploration.

jenny Downer
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how do i use binomial to show that 3^k C(n,k) = 3^k 1^n-k C(n,k)
 
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Did you type that correctly? Right now you have stuff = stuff * 1, which is clearly correct...
 
i wanted to explain a bit more
 
It should be
n
sum 3^k C(n,k) = 2^2n
k=0

the hint is 3^k C(n,k) = 3^k 1^n-k C(n,k)
 
The reason C(n, k) are called "binomial coefficients" is that C(n, k) is the coefficient of xk in (x+ y)n What are the coefficients of xk in (3x+ y)n? What do you get if x= y= 1?
 

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