Recent content by jeremyskate

Ok I did not understand the concept of temperature scale correctly this has shed some light https://en.wikipedia.org/wiki/Scale_of_temperature

Are you saying I simply need to solve R for the given conditions? Because that would give me a value of resistance not temperature and the exersice is to find the ideal gas temperature equivalent on the resistance scale.

The temperature is in celsius degrees not kelvin so the constant α is in celsius^-1 and β in celsius^-2 in order to negate t and t^2. This is a correction our teacher made after giving us the statement. Is that what you were celsius to?

Homework Statement IMPORTANT:There is an error in the statement.α and β are in C not K 2. Homework Equations R=Ro(1 +αt+βt2) The Attempt at a Solution I really don't know what to do because if I isolate t in the equation it will give me the temperature on the ideal gas scale whereas the...

v(0)=0 would make the most sense but since it isn't mentioned I also thought of leaving the constants and integrating them as well to get the position function, but the end result would have way too much undefined variables...

Homework Statement 2. Homework Equations [/B] v(t)=∫a(t)dt r(t)=∫v(t)dt The Attempt at a Solution f=ma a(t)=f/m a(t)=(4/5t^2i-3/5tj) (integrate) v(t)=4/5i(t^3/3+c1)-3/5j(t^2/2+c2) how can i get rid of the c1 c2?