Thermodynamics resistance temperature scale

Click For Summary

Homework Help Overview

The discussion revolves around the resistance temperature scale in thermodynamics, specifically addressing the relationship between resistance and temperature as described by the equation R=Ro(1 +αt+βt²). Participants are clarifying the temperature units involved and the implications of corrections made to the problem statement.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the correct temperature scale to use in the equation and questioning the implications of the constants α and β being expressed in Celsius rather than Kelvin. There is also confusion regarding how to isolate temperature from the resistance equation.

Discussion Status

The discussion is exploring various interpretations of the problem statement and the implications of the temperature scale. Some participants have provided clarifications regarding the units of α and β, while others are still grappling with how to approach the problem correctly.

Contextual Notes

There is a noted correction from the teacher regarding the temperature units, which has led to some confusion among participants about the proper application of the resistance equation. The original poster expresses uncertainty about the relationship between resistance and the ideal gas temperature equivalent.

jeremyskate
Messages
6
Reaction score
0

Homework Statement


Capture.PNG

IMPORTANT:There is an error in the statement.α and β are in C not K

2. Homework Equations

R=Ro(1 +αt+βt2)

The Attempt at a Solution


I really don't know what to do because if I isolate t in the equation it will give me the temperature on the ideal gas scale whereas the temperature I need to find is on the resistance scale.
 
Physics news on Phys.org
Re-read the problem statement: where is "K" used? What does the "correction" imply should be used instead?
 
The temperature is in celsius degrees not kelvin so the constant α is in celsius^-1 and β in celsius^-2 in order to negate t and t^2. This is a correction our teacher made after giving us the statement. Is that what you were celsius to?
 
Yes.
 
Are you saying I simply need to solve R for the given conditions? Because that would give me a value of resistance not temperature and the exersice is to find the ideal gas temperature equivalent on the resistance scale.
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K