Thermodynamics resistance temperature scale

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 2K views
jeremyskate
Messages
6
Reaction score
0

Homework Statement


Capture.PNG

IMPORTANT:There is an error in the statement.α and β are in C not K

2. Homework Equations

R=Ro(1 +αt+βt2)

The Attempt at a Solution


I really don't know what to do because if I isolate t in the equation it will give me the temperature on the ideal gas scale whereas the temperature I need to find is on the resistance scale.
 
Physics news on Phys.org
The temperature is in celsius degrees not kelvin so the constant α is in celsius^-1 and β in celsius^-2 in order to negate t and t^2. This is a correction our teacher made after giving us the statement. Is that what you were celsius to?
 
Are you saying I simply need to solve R for the given conditions? Because that would give me a value of resistance not temperature and the exersice is to find the ideal gas temperature equivalent on the resistance scale.