Recent content by jgiarrusso
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J
Solving Initial Value Problem with Implicit Solution
Homework Statement Solve the initial value problem (y+e^-y)y'=sinx subject to y(pi)=0 Homework Equations The Attempt at a Solution I'm not quite sure what to do with this one. I've scanned through my book and could find no similar problems in what we've done so far. I tried to...- jgiarrusso
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- Initial Initial value problem Value
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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J
Diff EQ Intro - Verify Family of Functions as Solution
So then dy/dx would be: dy/dx = e-x2 * ex2 - 2xe-x2\int(from 0 to x)et2dt - 2xc1e-x2 And then plugging it into the differential equation, it all cancels out. Thank you so much!- jgiarrusso
- Post #3
- Forum: Calculus and Beyond Homework Help
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J
Diff EQ Intro - Verify Family of Functions as Solution
Homework Statement Verify that the indicated family of functions is a solution of the given differential equation. Assume an appropriate interval I of definition for each solution. Homework Equations dy/dx + 2xy = 1; y = e-x2\int(from 0 to x)et2dt + c1e-x2 The Attempt at a Solution...- jgiarrusso
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- Diff eq Functions Intro
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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J
Finding the Arc Length of a Polar Function
Thanks! That's what I get for trying to do my homework far too late at night and without my list of identities nearby ~_~- jgiarrusso
- Post #6
- Forum: Calculus and Beyond Homework Help
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J
Finding the Arc Length of a Polar Function
Hmm, that did allow me to solve the integration (at least, I think I did it properly). But now, when I go to plug in my evaluation, I'm getting sec(π/2) which is doesn't work out. Using the half angle, I got (1-cosθ)=2cos2(θ/2). Plugging that in canceled out my 2sqrt2, and made the...- jgiarrusso
- Post #4
- Forum: Calculus and Beyond Homework Help
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J
Finding the Arc Length of a Polar Function
Aha, thank you so much. That was just the push I needed!- jgiarrusso
- Post #3
- Forum: Calculus and Beyond Homework Help
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J
Finding the Arc Length of a Polar Function
Hi, I've been having some issues in solving this problem. Homework Statement Find the arc length of r=2/(1-cosθ) from π/2 to πHomework Equations L =(integrate) sqrt(r2+(dr/dθ)2)dθ The Attempt at a Solution I found (dr/dθ) = (-2sinθ)/(1-cosθ)2 so (dr/dθ)2 = (4sin2θ)/(1-cosθ)4 Then r2 =...- jgiarrusso
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- Arc Arc length Function Length Polar
- Replies: 5
- Forum: Calculus and Beyond Homework Help