Recent content by jhahler

Homework Statement An 8-kg sphere A is moving to the left with a velocity of 15 m/s when it strikes the 45° inclined surface of a 10-kg block B which is moving to the right a 5 m/s. The ball strikes the block 1 meter above the ground. The block is supported by rollers and impact is perfectly...

Homework Statement integral of sqrt(x^2-36)/x) Homework Equations sqrt(x^2-a^2) = asec(u) Pythagorean identity The Attempt at a Solution I used trig sub on the x^2-36 and changed that to x=36sec(u) and dx= 36sec(u)tan(u). I simplified the square root in the numerator using...

Hi, I need to write a paper for my statics class on any new form of technology and it's impact on society. Does anyone have any suggestions for a topic? Any suggestions are greatly appreciated. Preferably something I can find articles about. Thanks in advance!

yes, bread18, i did mean \frac{sinx}{\cos(x)} Thanks by the way!

ok, I think I got this if anyone wants to confirm, still not sure about the x greater or equal to 0 and less than or equal to pi/2, but here goes. csc(x)sqrt(sec^2(x)-1) turns into csc(x)sqrt(tan^2(x)+1-1) after the Pythagorean identity, then simplifies to csc(x)tan(x) after you do the square...

gotcha, the Pythagorean identity 1+tan^2(x)=sec^2(x)

Ok! thanks Mentallic, Already posted second question, now I'm going to have to start using Latex.

Homework Statement Simplify this expression: csc(x)sqrt(sec^2(x)-1) with 0 less than or equal x less than pi/2. Homework Equations The Attempt at a Solution Not really sure what they want here, but would a good place to start be to square the entire expression to get rid of the...

ok, yeah I need to learn how you guys post on here in math terms instead of the keyboard, sorry for the confusion of 1/csc(x)+cot(x) being read as (1/csc(x))(cot(x)).. and yeah I just got lucky, because I didn't even think to multiply the top and bottom by the denominator. Thanks again! P.S. is...

ok guys, sorry, the inverse of csc(x)+cot(x) is 1/csc(x)+cot(x), and I saw the 1 on top and just thought it meant switch csc(x)+cot(x) to csc(x)-cot(x), making it equal to the other side, proving the identity, isn't that right?

OK! got it now, the -ln makes me take the inverse by raising the power to negative 1, then I put 1/csc(x)+cot(x) then the 1 on top goes away when I switch the sign on the bottom to negative. Awesome! So i didn't need to worry about the absolute value, or figuring out that csc(x)+cot(x) equaled 1...

when k = -1 does that mean take the inverse, like ln|1+cos(x)/sin(x)|^-1 ?

not sure how to relate lnx^k to this problem.. is x the function? what is k?

how do you get rid of the ln? does it have to do with multiplying by the inverse?

Trig identity with natural logs and absolute value?? Homework Statement -ln|csc(x) + cot(x)|= ln|cscx(x)-cot(x)| Homework Equations The Attempt at a Solution I got that csc(x)=1/sin(x) and cot(x)=cos(x)/sin(x), giving me a common denominator, added together I have...