Recent content by Jilang

Draw a straight line and see where the curve deviates for it the most.

Thanks Ruth! ; )

Why would you expect all properities to be entangled?

Hmm, the nose grows to its present condition. Is that not a state preparation?

I assume by not free you are regarding an electron as belonging to some atom or another. In an interaction it is not so clear cut.

If the gas is not a zero kelvin there will be Doppler broadening. http://www.phy.ohiou.edu/~mboett/astro401_fall12/broadening.pdf So the answer to your first question is in some part yes.

Quantum Field Theory for the Gifted Amateur by Lancaster and Blundell doesn’t have the 1/2, which is interesting! In that text the factors only appear when calculating the wave-function. So something is wrong with one of them...

Great thanks for confirming that. So wouldn’t you need four operators for 2 particles? Two to annihilate the two original states and two to create the new ones?

Maybe I’m not understanding your notation, but which operator in your first line annihilates the q state?

Isnt it there to avoid double counting?

Are you happy where the k! comes from? ( As that seems to be the difference)

Isn’t that two electrons confined to the same box?

You might have less consternation if you considered polarisation. The |H> and |V> states are clearly orthogonal and any other vector might be built from a sum of the two. However with spin the states of up and down states are orthogonal so it’s more tricky to picture.

For me, as I see it, the model breaks down at assumption 5. This assumption is written into agree with experimental results. But it explicitly states that B is a function of gamma. Given that gamma is dependent on the orientation of P1 this implies that B depends on said orientation. This is a...

You state that “It is assumed that a photon can be simultaneously in different p-states depending on the value of a parameter λ and a chosen direction relative to the polarization of the photon. That means some of the photons with polarization α are also in p-state β and thus pass a polarizer...