Your implication is that the resistance of the switch device is the culprit. If so, replace the semiconductor with a mechanical knife switch. Not fancy, byt effectively 'no' resistance.
Your problem may be the resistance of the capacitors.
Look for low ESR (Equivalent series resistance)...
When the object is just launched it has E Cos (60) energy in the horizontal direction and E Sine (60) in the vertical direction. When it arrives at the top end of travel (vertically) it only has the horizontal energy left.
Therefore it is E Cos (60) = 0.5 E
Since the slope is not constant, the resistance is not constant. You need to separate small signal effects and large signal effects. For instance if you put current thru the resistor such that the slope significantly changes, then the Small signal resistance is the slope at that point. If you...
Convert the thevenin equivalent norton equivalent, that is a shunt resistor and a current source equal to the thevenin voltage divided by 100 ohms. The current source is supposedly infinit so doesn't affect the input impedance calculation.
Clearly the input impedance is 100 ohms.
Joe
The feedback resistor limis the gain at DC to 100. If it was not there the theoretical gain at DC would be infinit. Any small input offset would cause an integration that would eventually saturate the op amp. Then all the usual assumptions about op amps go to H@$^*.
Joe
My recommendation is nanotechnology. It's new (Exciting) and will start growing like a weed. You will be one of the pioneers. VLSI stuff is also good, but you will need to work hard to come up to speed. The industry is now well established.
Good luck.
Joe