Recent content by jonny23

but will the liquid exert a force on free end of tube ??

Homework Statement If there is a horizontal tube rotating on axis in horizontal plane. it is filled with an ideal gas , So which end will the pressure be higher ? the end on axis?? or the free end Homework Equations P.A= m .w^2 .r The Attempt at a Solution i think the free end should have...

But in solution( i have checked in 4 books) says it will not change since we have set constant potential gradient across the wire.. and i don't even understand it

Homework Statement if a potentiometer has driver cell and wire AB ,then an unknown emf (emf<driver cell) is balanced at some length L. does the balance point change if internal resistance of driver cell is changed? Homework Equations V= kl K= potential gradient The Attempt at a...

because in experiments, 2 litre hydrogen gas combined with 1 litre oxygen gas . and by chemical reaction we know 2 H2 + O2 ----> 2 H2O so 2 litre hydrogen contains double number of atoms than 1 litre oxygen ( Provided other conditions like pressure temperature of both...

then i am getting tan^-1 (a/g) But i think its not right because if you put a =0 then the free surface would be horizontal but shouldn't it be paralllel to incline?

this is the general equation which i derived. See following CASES : if a=0 you see the equation gives angle of free surface as (alpha) if a< g tan(alpha) where (alpha) is angle of inclined plane, then block moves downward wrt to inclined plane and free surface is given as per equation if a =g...

i got this

so are they parallel to yz plane or on the yz plane

the particle move perpendicular to x-axis but arent they in xy plane

Homework Statement A transverse wave travels along x-axis . what is direction of oscillation of particles ? Homework EquationsThe Attempt at a Solution I think the answer is xy plane but Wikipedia says its yz plane . Please explain how?

in frame of the vessel we apply pseduo force on a liquid particle that is ma = mgsin(thetha) - u mgcos(thetha) and the downward force i.e. mg . The resultant of the two should be perpendicular to the surface.

it should be tan^-1(u) with the incline...

i guess that it will be parallel to inclined surface .as the net force should be perpendicular to liquid free surface and the so liquid sholud be parallel to surface. am i right?

ya it will be horizontal when stationary but please explain what happens when it accelerates