Recent content by jony529
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Resistance and resistivity problem
The thrilling conclusion to my problem: rho = rho(i)alpha(T-T(i)) + rho(i) R = rho(L/A) Find R. {(L/A)} * {rho} = {(L/A)} * {rho(i)alpha(T-T(i)) + rho(i)} which equals R = R(i)alpha(T-T(i)) + R(i) 2250 ohms = 634(4.4x10^-3)580 + 634- jony529
- Post #6
- Forum: Introductory Physics Homework Help
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Resistance and resistivity problem
BTW the answer is 2250 ohms. Like I said originally it was a quiz online I just took. But how do I arrive at that answer??- jony529
- Post #4
- Forum: Introductory Physics Homework Help
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Resistance and resistivity problem
Sorry but I didnt fully understand what you were trying to tell me. I know R = rho(L/A), So if I pick an arbitrary length say 10m. How do I find that A of the wire, and furthermore what's canceling out? Confused!- jony529
- Post #3
- Forum: Introductory Physics Homework Help
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Resistance and resistivity problem
Hey I had a question on my quiz where it asked for the Resistance of aluminum at 600 deg C. But the formula rho-rho(i) = rho(i)a(T-T(i)) only finds the value of the resistivity at 600 deg C how do I convert it to resistance without more given info? Question: A spool of aluminum wire has a...- jony529
- Thread
- Resistance Resistivity
- Replies: 5
- Forum: Introductory Physics Homework Help