Recent content by Josh225

Homework Statement See image attachedI don't understand why Va is 20 volts instead of it being 5 volts or a combination of the two. The same goes with Vb. I can see (but I am likely looking at it the wrong way) why Vc is 8 volts.. Because Vc is right next to the voltage source. Can anybody...

Im not 100% sure by what you mean by making a sketch. I thought 26.7 kilohms would be the total resistance within the circuit (by adding the 2 resistors together). If not, how would you do so? Here is my sketch, but am unsure it this is what you were suggesting.

Homework Statement See image attached. I am currently stuck on part b. Homework Equations (Rt) (Rint) / Rt + (Rint) The Attempt at a Solution I thought that Rt would be 26.7 kohms, but my answer is not matching up with the answer in the book. I am unsure why since the resistors are in...

Yeah... It turns out I just plugged the wrong numbers. I put R1 where R2 was supposed to be and vise versa Dumb mistake. Thanks!

I assumed 2.2 would be R1 since it is closest to the power supply and 4.7 would be R2.

I used the second one, V2 = R2/ (R1+R2) V

Alright, so since the 3.3 kΩ does not have current, I can essentially ignore it. Next I use the voltage divider rule and do 2.2 kΩ/6.9 kΩ (9)= 2.87 This is where I really am unsure if I just got lucky since I had expected to get the correct answer from the voltage divider rule.. I then...

Homework Statement See image attached Homework Equations Voltage divider law? Ohms law? The Attempt at a Solution I am unsure on how to treat the problem since I have only learned how to find information within parallel circuits and series circuits. I tried to use the voltage divider law...

Homework Statement I got the correct answers for A and B, I just need help with C and D. A. Find indicated currents. I1= I2 = 3 A ... IL = 6 A B. Find total power delivered by each source. PE = 12 V (3A) C. Find the total power delivered by each source and compare it to the power delivered...

Oh! I see. Thank you for the info!

Strange.. In my book it's expressed as 31.7 μm2.

Oh dang haha. Quite a difference. So it would be 31.7 μm2... Which would actually equal 3.17E-5 m, right?

Hmmm I was under the impression that "μ" meant permeability and the letter following it represented a specific number (μo = 4 pi x 10-7) (still can't find that pi button on here!). I kinda "cheated" and looked up some of the conversion.. I really do need to practice them, but to find "A" I...

Also, when I plug all the correct numbers in and run the equation through, it comes out to .01568 and I have to move the decimal 3 places to the right (like the answer is in meters and I need to convert to millimeters). I am honestly not so hot wih unit conversion, so I was wondering what an...

Thanks!