Power delivered to each source. Image included

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SUMMARY

The discussion focuses on calculating the total power delivered by each source in a circuit with two batteries and a load resistance (RL). The correct total power delivered is 72 W, derived from the equation PE = E * Is, where PE is the power, E is the voltage (12 V), and Is is the current (3 A). The participant expresses confusion regarding the relationship between the power delivered and the load, as well as the implications of symmetry in the circuit regarding power distribution between the two sources.

PREREQUISITES
  • Understanding of Ohm's Law (V = I * R)
  • Familiarity with electrical power calculations (P = V * I)
  • Basic knowledge of circuit analysis involving multiple sources
  • Concept of power dissipation in resistive loads
NEXT STEPS
  • Study the principles of power distribution in parallel circuits
  • Learn about circuit symmetry and its implications on power delivery
  • Explore advanced circuit analysis techniques using Kirchhoff's laws
  • Investigate the effects of varying load resistance on power calculations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing power distribution in electrical circuits.

Josh225
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Homework Statement


I got the correct answers for A and B, I just need help with C and D.

A. Find indicated currents. I1= I2 = 3 A ... IL = 6 A

B. Find total power delivered by each source. PE = 12 V (3A)

C. Find the total power delivered by each source and compare it to the power delivered to the load RL.

D. If only source current was available, what would the current drain be to supply the same power to the load? How does the current level compare to the calculated level of part A.

Homework Equations


PE = E Is

Is = E/ RT

The Attempt at a Solution


A. Find indicated currents. I1= I2 = 3 A ... IL = 6 A

B. Find total power delivered by each source. PE = 12 V (3A)

C. It says the answer is 72 W, but I am unsure how to get there. I figured that I would find RL by applying ohms law (R= V/I ... R=12/3 = 4 ohms) then subtracting it from PL (72 W), but that gets me the wrong answer.

D. For D, I am not so sure..
 

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C is a question (find the power) followed by an instruction (to make a comparison). The question part looks identical to question B, other than an apparently unimportant 'the'. Are you sure you have typed in the questions correctly?

Also, if we are told that 72W is being dissipated in the resistance, doesn't the symmetry between the two batteries in the circuit dictate that each must be supplying half of that power, without having to do any calculations?
 

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