Thank you so much for your reply!
b = <b1, b2, ..., bn>
c = <c1, c2, ..., cn>
b + c = < (b1 + c1), (b2 + c2), ..., (bn + cn)>
We know:
Ab = 0
s.t. 0 = Ab1, Ab2, ..., Abn
Ac = 0
s.t. 0 = Ac1, Ac2, ..., Acn
=> Ab + Ac = <(Ab1 + Ac1, Ab2 + Ac2, Abn + Acn)>
=> A(b+c) =...