Recent content by Jscrub

Nevermind...I got it

I got B...but I don't know how to figure out theta?help!

I got: Fn=mg-I*l*b*cos(theta)? So that I*l*b*cos(theta)=(mg-I*l*b*sin(theta))*.55? Or did I mess up my expression for Fn? I don't really know what to do from here... CAN ANYONE HELP WITH THIS PROBLEM PLEASE...IT IS DUE IN 2 HOURS...

FN + FB-vertical = mg __________________ This equation says FB and FN are in the same direction...which means mg and friction are in the same direction..I don't understand how this works... If the force is pushing it to the left or right, wouldn't friction and Fb be to the left and right

the equation does not incorportate friction...

I figured... F=ma, FN=mg, friction=usFN, which means friction = (us)mg friction is pushing against the force moving it... I ended up with f=mgus...plugged it into F=ILB, Or B=Fmax/IL...I got O.22/(40A)(.2m) =.0275T...which is not right...can someone help me please!

I understand how to do free force diagram..I just don't understand how this one is supposed to be...is the fn force coming from the other rod?? When it talks about the rod sliding...what is it sliding on?

In this situation would sumF =mg-Fn...however I know that I would have to incorporate the us coeff. , which is related to Fn if I remember from Physics I... not sure how to draw the free body diagram for this picture...

But they are 90 degrees from one another so wouldn't it be Fmax = ILB

The only equation I have with I: F = ILB sin (theta)

Magnetism problem for General Physics 2! Homework Statement Suppose the rod in the figure has mass m= 0.40kg and length 20cm and the current through it is I= 40A . (Intro 1 figure) If the coefficient of static friction is us= 0.55, determine the minimum magnetic field (not...

The above was not a conclusion..it was just a reply to the previous person... Co = 3500E-9... But it is fine..I don't need anymore help...I figured it out... Thanks

v= 32 V K(mica) = 7 K (air) = 1.0006 so, Co= 1.12E-4

c= KCo c=Q/V Q Air = 1.12E-4

I cannot figure out this problem...can someone help me? A 3500 air-gap capacitor is connected to a 32 battery. If a piece of mica fills the space between the plates, how much charge will flow from the battery? Express your answer using two significant figures.