Physics Homework problem: Dielectrics

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SUMMARY

The discussion revolves around a physics homework problem involving a 3500 air-gap capacitor connected to a 32V battery, with a piece of mica introduced as a dielectric. The initial charge flow from the battery when the capacitor is filled with air is calculated to be 1.12E-4 C. The dielectric constant for mica is noted as K(mica) = 7, which affects the capacitance of the capacitor. The final capacitance with the dielectric is determined using the formula c = KCo, where Co is the original capacitance.

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  • Understanding of capacitor basics, including capacitance and charge.
  • Familiarity with dielectric materials and their impact on capacitance.
  • Knowledge of the formulas: c = Q/V and c = KCo.
  • Basic algebra skills for manipulating equations.
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Jscrub
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I cannot figure out this problem...can someone help me?

A 3500 air-gap capacitor is connected to a 32 battery.

If a piece of mica fills the space between the plates, how much charge will flow from the battery?


Express your answer using two significant figures.
 
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Welcome to PF!

Hi Jscrub! Welcome to PF! :wink:

First, how much charge will flow from the battery when the gap is just air?

Second, what equations do you know about how a dielectric affects a field or a capacitor? :smile:
 
c= KCo

c=Q/V

Q Air = 1.12E-4
 
v= 32 V

K(mica) = 7

K (air) = 1.0006

so, Co= 1.12E-4
 
Jscrub said:
A 3500 air-gap capacitor is connected to a 32 battery.

What is a 3500 air-gap capacitor?

Is that a 3500μf capacitor or 3500nf?

What is the effect of the dielectric on the capacitance?

I don't follow your conclusion
so, Co= 1.12E-4

Haven't you added a dielectric to your capacitor?
 
The above was not a conclusion..it was just a reply to the previous person...

Co = 3500E-9...

But it is fine..I don't need anymore help...I figured it out...

Thanks
 

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